((2b)(b))^2=(2b+6)(b+40)

Solution for ((2b)(b))^2=(2b+6)(b+40) equation:

((2b)(b))^2=(2b+6)(b+40)

We move all terms to the left:

((2b)(b))^2-((2b+6)(b+40))=0

determiningTheFunctionDomain
2bb^2-((2b+6)(b+40))=0

We multiply parentheses ..

-((+2b^2+80b+6b+240))+2bb^2=0


We calculate terms in parentheses: -((+2b^2+80b+6b+240)), so:

(+2b^2+80b+6b+240)

We get rid of parentheses

2b^2+80b+6b+240

We add all the numbers together, and all the variables

2b^2+86b+240

Back to the equation:

-(2b^2+86b+240)


We get rid of parentheses

-2b^2-86b+2bb^2-240=0

We move all terms containing b to the left, all other terms to the right

-2b^2-86b+2bb^2=240